Video summary
The video begins by distinguishing between two fundamental concepts regarding triangles: congruence and similarity. Two triangles are considered congruent if all their corresponding parts, including angles and side lengths, are identical; essentially, one triangle is just a translation, rotation, or reflection of the other in space. In contrast, similar triangles share the same shape because their corresponding angles are equal, but they do not necessarily have the same size. This means that while congruent triangles must be exact copies of each other, similar triangles can differ in scale; for instance, one triangle might be twice as large as another while maintaining the exact same proportions and angle measures.
A key property defining similarity is proportionality, where the ratios of corresponding side lengths between two similar triangles are always equal to a constant factor known as the scale factor. The video illustrates this with an example involving a spotlight casting a shadow on a wall, creating two right-angled triangles that share a common vertex angle at the light source. Because these triangles have matching angles (one being a right angle and sharing another acute angle), they are similar regardless of their different sizes. By setting up a proportion between the height of the man and his distance from the light against the total shadow height and total distance, one can solve for unknown lengths like the height of the shadow on the wall using simple algebraic manipulation based on these ratios.
The lecture further applies this concept to real-world calculus problems involving changing quantities, such as water filling an inverted conical tank. In this scenario, the cross-section of the cone forms a right triangle where the radius and height are related through similarity principles. Whether calculating the specific radius at a fixed water level or deriving a general formula for how the radius changes as the gap between the water surface and the top of the tank varies (treating that gap as a variable $x$), the solution relies on establishing proportions between similar triangles formed by the full cone and the partial volume of water. This demonstrates why understanding similarity is crucial in calculus, as it allows students to model systems where variables change while maintaining geometric relationships, enabling them to derive formulas for rates of change without needing complex integration immediately.
Read the full video transcript
so now we can talk about the main idea
for lecture three so what does it mean
for two triangles to be the same or what
does it mean for two triangles to be
similar so we say that two triangles ABC
and DF are congruent if all of the
corresponding parts are congruent that
is the triangles ABC are is congruent to
DF if angle a is congruent to angle D
angle B is congruent to angle C uh angle
e excuse me angle C is congruent to
angle F the side AB is congruent to De
the side AC is congruent to DF and the
side BC is congruent to EF and so if we
think about the possible drawings we
could get from such a thing we say that
two triangles are congruent maybe
something like
this if when labeled so we have like
labels a b c d e f so we require that
angle a be congruent to angle D we have
that angle B is congruent to angle e we
have angle C is congruent to angle F so
they have the exact same angles um and
also in terms of side lengths we have AB
is congruent to De we have that CB is
congruent to Fe and we have that uh side
AC is congruent to DF that's what it
means for two triangles to be congruent
to each other all of the corresponding
parts are congruent as angles and and
line segments and so note that congruent
triangles are essentially just the same
triangle but possibly in different
locations in the plane uh so like the
difference between ABC and DF is just
translation I moved triangle ABC you
could also throw Reflections and
rotations in the mix there but the two
triangles are essentially the same
although they might be oriented in
different places in the plane okay a
weaker notion than congruence is the
idea of similarity we say that triangles
ABC and DF are similar if just the
angles are congruent to each other so if
angle a is congruent to angle D angle B
is congruent to angle e and angle C is
congruent to angle F we say the
triangles are congruent to each other
excuse me they're they're similar to
each other and we don't use the usual
congruent symbol we just draw a little
squiggle um to say that two triangles
are similar to each other well if two
triangles are congruent they definitely
are similar but it's not necessarily the
case that if two triangles are similar
that they have to be congruent for
example we could draw a picture like the
following so drawing back our labels
here so we have AB
C and we have D
EF and I apologize that this picture is
not perfectly drawn to scale but you'll
notice that angle a is still congruent
to angle B angle e is still congruent to
B and angle C is still congruent to F so
these triangles are similar to each
other but they're not congruent you'll
know notice that the side lengths of the
two triangles are different the DF
triangle is much bigger than ABC but
even though the side lengths are bigger
they have still the same basic shape
because the shape of a triangle is
determined by its angles not by the side
lengths and so when it comes to similar
triangles similar triangles have
corresponding parts that are that are
proportional so AC and DF are
proportional to each other that is the
the factor which de is larger to AB is
the same as the factor as AC as well and
so what we see here is if we look at the
proportions here if you take
AC the the length there and divide it by
DF this is equal to the same thing as AB
/ de which is the same thing as BC
divided EF and these are all equal to
some constant so like maybe the triangle
is twice as big or three times as big or
1 and a half times as big this is what
we get by proportionality these ratios
are always the same and so because of
this similar triangles using this notion
of proportionality is a very very useful
tool in trigonometry and calculus and
Beyond and so I want to demonstrate some
examples of how you can set up
proportions for similar triangles so
consider the two triangles you see on
the screen ABC and DF these triangles
are congruent to each other excuse me
they're similar to each other because
their angles are congr congruent A and D
are congruent angles B and E are
congruent angles and F and C are
congruent angles so these triangles are
similar we know the three side lengths
of triangle ABC um the side AC is worth
is length 16 side AB is 24 and CB is 32
but we only know the proportion for FD
well because they're proportional if I
take the segment AC over DF this is
going to equal the this is going to
equal the same fraction for the other
corresponding parts so we get that AB /
de would equal that and BC over Fe these
are all going to equal each other some
constant and so let's fill in the
information we know so a c is 16 DF is 8
um which if you simplify just that
fraction right there you get a two and
so that's that constant K this triangle
ABC is twice as big as DF and so all the
other sides are going to satisfy that
same proportion so you get that if we
take for example ab ab was equal to 24
and if we take de which we don't know
what that is we get that
de like so uh 2 is equal to 24 over de
that's to say that 2 * de is equal to 24
or D equal 12 so the missing side here
was 12 um the other one as well if we
just cut this in half that's going to
give us the side length for Fe as well
so that means the remaining side must be
16 because there's a there's a factor of
two uh proportionality between these
triangles let me give you some examples
that I use in my actual Calculus class
uh you can actually see the links to
these videos uh on the page right now so
these are genuine calculus problems and
I just want to demonstrate not the
calculus part but why similar triangle
become essential to some of these
calculus problems so imagine a spotlight
is on the ground and it shines on a wall
That's 12 M away so here's our Spotlight
here's the wall and the distance between
them is going to be 12 M so we know
about that so there's a man who's who's
between the wall and the spotlight and
he himself is 2 m tall which I remember
from Jurassic Park that's how tall a
velociraptor is as well so he's a pretty
tall dude not not like unhuman tall but
you know he's on the taller side of
things so if he's 2 m tall and he's
standing between the wall and the
spotlight the Sha there's going to be a
shadow of the man on the wall so like as
you see in this diagram here the the
light shines but as it hits the man it
obstructs the light and so there's a
shadow on the wall here let's call why
the height of the Shadow okay if the man
is exactly 4 M from the
building um how tall is the shadow how
tall is the shadow here and so if he's 4
M from the building building that means
since the the the spotlight and the wall
are 8 m apart he'd be 8 m away and so
you can take 12 - 4 that's where this 8
came from just so you're aware so what
we want to consider here is consider
this triangle right here and I'm going
to use a different color to emphasize it
we're going to draw this one in red
let's look at the triangle that's formed
between the spotlight and the man and
we're just going to extrapolate it for a
second over here if we just look at that
triangle then notice that this side
right here is eight
this side right here is two uh and let
me mention that this is a right angle
this is a right triangle because the man
is standing up right um now let's
consider the the triangle that's formed
between the spotlight and the
wall so this green triangle over here
let's bring it over to the side so if we
draw that again I'm just going to draw
it much
bigger the distance between the
spotlight and the wall is going to be 12
and then the height over here is y we
don't know what it is but what we do
know is that this is also a right
triangle but it's not just that we know
that this angle formed from the
spotlight is the angle in both of these
triangles so we have a right triangle
which have two angles that are congruent
then because the angle sum of a triangle
always equals 180° if you have two
triangles where two of the angles are
the same then the third angle must be
the same as well in a right triangle the
two non-right angles are necessarily
complementary to each other so because
of that the angle or the triangles have
to be similar if a right if two right
triangles share a common angle that mean
they have all angles the same they're
similar so we can set up a
proportionality argument here so notice
that y over 2 corresponds to 12 over 8
so Y and two go together and 12 and 8 go
together so y over 2 corresponds to 12
over 8 so if he times both sides by two
to clear the
denominators well at least to clear the
denominator on the right hand side
you're going cuz we're trying to solve
for y the height of the the height of
the Shadow you get y = 24 8 which 8 goes
into 24 3 times and we see that the
height of the Shadow would be 3
m let me give you another example coming
directly from my own calculus course we
have a tank uh of water that itself is a
inverted cylind uh circular cone right
here so it's kind of like an ice cream
cone it points downward like this
although this diagram right here we're
looking straight onto it and we just see
a triangle as this cross-section the
height of this cone is going to be 12 M
the radius of the cone is going to be 4
M as labeled right here this water
there's water that's filled into the
tank and so the height of the water is
going to be 8 m so the tank is not
completely filled the height is going to
be 8 m and so particular there's a gap
of 2 m at the top of this that we could
add two more meters of water into this
tank right here so let's figure out what
the radius of the water is at this
specific height so this unknown value is
R what will be the radius CU when you
fill when you fill the tank with water
the tank as the water as a fluid will
take the shape of its tank so what's the
radius of the water that has this conle
shape right here well again we could
make a similar triangle argument so the
first one I want you to think about is
if we look at the whole tank we could
take this whole triangle right here but
to make life a little bit easier I'm
actually going to take half of the
triangle this is an example of an esos
triangle and we're going to cut the
esles triangle in half which always
gives you a right triangle so let's look
at this triangle right here pull it off
over
here so the triangle in
yellow uh this side length is going to
be the height of that triangle which is
10 m this side length is going to be the
radius which is 4 M so we have that it's
a right triangle and notice that this
angle at the bottom right here is just
this angle right here next let's look at
just the triangle involving the water
again we're just going to take half of
it pull this over here to the side we
get a triangle that looks like this the
height is going to be eight that's given
to us the radius we do not know and
again this is the same angle in play
right here so these angles are congruent
right angles are congruent to each other
so the other two angles have to be
congruent to each other uh these
triangles are similar to each other so
we can set up proportions so this tells
us that R over4
corresponds to 8 over 10 for which we
can times both sides by four this would
give us that R equals 8 * 4 over 10
which is going to give you 32 over 10
which gives you
3.2 met as the radius of the water at
this point in the tank suppose we want
to next find the radius R when the
height of the water is itself a variable
okay what if we allow the gap between
the top of the tank and the water level
what if we call that X so in the example
we did first X if the height was eight
then X was equal to two Okay so what if
we allow that variable to come into play
right here then the height of the
water the height of the water is just
going to be 10 - x whatever the Gap
turns out to be and so that then leads
to the proportion that R over 4
corresponds to the height which is 10 -
x all over 10 in which case then we can
solve for R easy enough we get R is
equal to 4 * 10 - x all over 10 four and
10 both have a common factor of two
which you can cancel out and so we see
see that the radius is equal to 25s * 10
- x which we can then check our answer
if we take X to B2 like we saw before uh
that would look like 2
fths take 10 - 2 which is going to be 8
2 over 5 * 8 2 * 2 Excuse Me 2 * 8 is 16
over 5 which 16 over 5 is the same thing
as 32 over 10 which is the same thing as
3.2 this gives us the answer we did
before and so this is the idea you know
uh why similar triangles can be very
important in a calculus setting calculus
cares about like when when you take
these quantity and treat it like a
variable how does the system change well
no matter how you change the system it's
always a similar triangle so we can find
a formula for the radius depending on
the height of the water or in this case
the gap of the water and and it's always
this form is always set up by a similar
triangle argument so for calculus
students being able to set up and use a
similar triangle argument is very very
important which is why we want talk
about it in this trigonometry class