Video summary
A heat pump operates as the exact thermodynamic reverse of a heat engine, functioning by moving heat against its natural tendency rather than utilizing it. While a heat engine naturally allows heat to flow from a hot reservoir to a cold one to perform work, similar to water flowing downhill to turn a wheel, a heat pump requires an input of work to force heat to flow uphill from a colder environment to a warmer space. This process is not spontaneous; just as pumping water from a low level to a high elevation requires energy, extracting thermal energy from cold outdoor air and transferring it into a warm house demands electrical work. Common examples of this technology include refrigerators, air conditioners, and central HVAC systems, all of which remove heat from a cooler interior area and reject it to a warmer exterior environment.
The performance of a heat pump is measured not by efficiency in the traditional sense, but by a metric called the Coefficient of Performance (COP), which represents the ratio of useful heating or cooling benefit to the energy cost required to operate the system. When used for heating during winter, the COP is calculated as the hot temperature divided by the difference between the hot and cold temperatures. In this mode, the "benefit" is the total heat delivered into the warm space, which includes both the work supplied as electricity and the heat extracted from the outdoors. Consequently, the COP for heating is typically greater than one, meaning that for every unit of electrical energy consumed, the system delivers multiple units of thermal energy to the home.
Conversely, when a heat pump operates in cooling mode, such as an air conditioner or a refrigerator, the definition of the benefit shifts to the amount of heat removed from the cold interior space rather than the total heat rejected outside. In this scenario, the COP is calculated using the cold temperature divided by the temperature difference, resulting in a value that is mathematically lower than the heating mode but still generally exceeds one. This high performance explains why heat pumps are significantly more energy-efficient than direct electric heaters or gas heaters; while a standard heater converts every joule of electricity directly into heat with a maximum efficiency of 100 percent, a heat pump leverages existing thermal energy from the environment to generate two to twenty times as much heat for the same amount of electrical input. Ultimately, the technology demonstrates that by supplying work to pump heat uphill, we can achieve substantial heating or cooling effects that far surpass simple conversion methods.
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[Music]
all right so we have an understanding of
what a heat engine is heat engine is a
process that converts heat into work
specifically by absorbing some amount of
heat from a hot temperature reservoir
using some of that heat to do work and
having some leftover heat that it
rejects to a cold temperature reservoir
several times when talking about heat
engines we've talked about the need for
those processes to be reversible
so if in fact they're reversible let's
think about what happens if we actually
reverse them if we
change the direction of each of these
arrows so remember the arrows indicate
whether energy is flowing into the
system or absorbing heat or whether it's
flowing out of the system we're
rejecting heat or we're doing work
so if i redraw this figure just
reversing each of these arrows
so
the hot
heat process is
flowing from the system to the
surroundings
the work is being done on the system
rather than by the system
and at the cold temperature heat is
flowing
out of the surroundings into the system
i've just reversed all those arrows
let's think about what that means if
this process involves
absorbing some heat at a high
temperature using some of it to do work
and letting the rest of it flow down to
the cold temperature
let me point out that
it's no accident that i've drawn this
figure with the hot temperature on top
and the cold temperature on bottom it's
it's a very natural process for heat to
flow from the hot temperature to the
cold temperature
in fact when carneau came up with this
idea of heat engines and this way to
describe them
he was thinking of something like a
waterfall where it's very natural for
water to flow from a high position to a
low position and you can make use of the
natural tendency for water to flow
downhill to turn a water fill a water
wheel to get some work out of the
process as water flows from high to low
same thing here heat will naturally flow
from a hot temperature to a cold
temperature we can make use of that
natural tendency to do some work along
the way
when we reverse the process what these
arrows describe is we're absorbing some
amount of heat from a cold body from a
cold
reservoir
we're going to
put
some amount of heat
up into a hotter temperature so i've got
a net amount of heat flow from a cold
temperature to a hot temperature that's
not a natural thing to happen it doesn't
normally happen that heat flows from a
cold thing to a hot thing so we have to
actually do some work it costs us some
energy
in order to pump the heat from the cold
temperature up to the hot temperature
just as it would cost us some energy to
pump water from a low level up to a high
level
so
in analogy with that statement
this process is called a heat pump
and it's just the exact reverse of a
heat engine
some examples
of heat pumps would be
things like
a refrigerator
so that's exactly what we expect a
refrigerator to do
we think of refrigerator as a way to
cool down our food but we have a cold
inside of a refrigerator and we need to
remove some heat from that cold place
and we end up putting that heat in a
hotter place so when you bring your
groceries home and you put them in the
refrigerator you want to remove some of
the heat that's keeping those groceries
at room temperature you want to cool
them down so you're removing heat from
the
place from the cold surroundings costs
you some electricity to do that and then
you dump that excess heat out the back
of the refrigerator
so that's exactly what a refrigerator is
doing it's also exactly what an air
conditioner does
if you have a window air conditioner in
the window of a room it's removing heat
from the cool inside of your house
cooling it down further and dumping that
excess heat out the window
to a place that's probably warmer
another example and this one is is
perhaps the one to keep in your mind for
the rest of this
video because it's it's
the best illustration and also the most
confusing illustration of this idea of a
heat pump
so it's worth getting the details
correct what we call a heat pump in a
central air hvac system for a house for
example is an example of a heat pump
in the summer your heat pump works the
same way as an air conditioner it's hot
outside it's cool inside you want to
keep it cool so you want to remove some
heat from the inside and dump it out to
the warmer outside so that's exactly
what this heat pump is doing
counter intuitively what your heat bump
does in the winter
when you
warm up your house you know it's cold
outside warm inside you want to make
sure it stays warm inside so the way the
heat bump works in the winter is
it it uses exactly this process it
extracts some heat from the outdoors
from the cold winter outdoor air it
extracts some heat from the cold air and
dumps it into your house so your house
is like the the place where the waste
heat goes and you're using that waste
heat to heat up your house so heat pump
when you run it in the winter time
it's removing heat from the outdoors
dumping it into your house
so
heat
pumps what we want to say about heat
pumps is oh yes their efficiency how do
we talk about the efficiency of a heat
pump
uh efficiency of a heat engine we've
we've talked about before it's related
to this ratio of temperatures t cold to
t hot
the efficiency of a heat pump we don't
actually end up calling it
efficiency
so we're going to use a different term
we're going to use beta
this term beta
we call it coefficient of performance
and it will become clear in just a
minute why i'm not going to call that an
efficiency
the coefficient of performance or cop
for heat pump that's still
philosophically going to be the amount
of benefit
energetically we get from the heat pump
relative to how much it costs us
to run the heat pump
the definition of what the benefit is
what the cost is
depends on whether we're using it to
heat something up or cool something down
but the the basic idea is still the same
so let's think about
let's say first
when we're using the heat pump to heat
something up when we're running this
heat pump in the winter and our benefit
is the heating effect that we get from
the heat pump you're using your heat
pump to heat your house so
the benefit you get from this heat pump
is
you pay some electricity to do some work
to pump
in this unnatural direction remove some
heat from the cold outdoors and pump it
into your warmer house so the benefit
you're getting is this q sub h
the cost
doesn't cost you anything to remove the
heat from the outside the cost to you is
the amount of work that you have to do
the electricity you have to pay to make
this heat pump run
so that's
the cost let me make sure i have my
signs right qh is a
negative number so i want to make that
negative on top so that the benefit to
us is a positive amount of of heat so
that's negative of this negative
quantity and work is already a positive
number so i'm going to leave that just
the way it is
so
the way i can make sense out of this is
the same thing we did before whether i
look at this diagram or whether i look
at this diagram
the net change in energy of the system
has to be zero if i combine all these
arrows together so if i add up total
amount of heat
and total amount of work that has to be
0
so that
let's say
w is going to be minus qh minus qc
so that's what i'll put in the
denominator here
i've got minus qh on top
minus qh minus qc
on
bottom and that's too many negative
signs so let me just get rid of all of
them at the same time so qh over qh plus
qc
i want eventually to turn those q's into
temperatures the way we did when we were
talking about the energy i mean the
efficiency of a heat pump remember we
used the fact that
the ratio of the heats is the negative
of the ratio of the temperatures
so
maybe not the shortest but the
way i can guarantee i won't make any
mistakes
let's divide through top and bottom by q
sub h
so qh becomes 1 qh becomes 1 qc becomes
qc over qh then i've got this ratio qc
over qh
which i can write as
negative tc over th
and now that i've done that i don't like
the way it looks with a fraction inside
a fraction so let me go through and
re-multiply by th in this case
and what i'll get is
so one becomes th one becomes th and tc
over th becomes tc
so the efficiency sorry not the
efficiency the coefficient of
performance
for a heat pump being run in heating
mode
is this ratio hot temperature divided by
hot minus cold
so
similar to
efficiency of a heat engine in a sense
that involves just the ratio of
temperatures or difference in
temperatures but it's a different
combination of those
we'll plug some numbers in in just a
minute and see what kind of values we
get for this coefficient of performance
but before we do that
let's run through the same calculation
real quick
if we're using our
heat pump in cooling mode rather than in
heating mode so if we're
using
our heat pump as an air conditioner as a
refrigerator where the benefit we get to
us is how much heat it removes from the
inside of the refrigerator or the
inside of the house when we're using our
air conditioner or our heat pump so in
this case the benefit that we get isn't
the amount of waste heat that's dumped
out the back of the refrigerator or out
the
outside the house when you're cooling
your house the benefit we get is how
much heat we extract from the inside of
the house so the benefit we get is
qc
which is a positive number i want to
divide that by
the electricity cost or the amount of
work i have to do in order to pump that
heat up hill to the higher temperature
reservoir
so again the algebra is going to be
almost the same but not quite
the work in the denominator
is minus qh
minus qc
um
let's again flip the signs i want to
make these positive and that one becomes
negative
so i've got
if i divide through in this case again
by qh
i'll get
minus qc over qh
over 1 plus qc over qh
now i can use
the fact that the ratio of heats is
equal to the negative the ratio of the
temperatures
so that'll be
negative becomes positive tc over
in the denominator i've got 1 minus t c
over t h
and then if i get rid of the fractions
inside the fractions multiplying by t h
gives me
t c
over t
c
no sorry t h
minus t c
notice that this result
for cooling is not the same as this
result for heating when i'm heating the
coefficient of performance is hot
temperature over the difference in
temperatures when i'm cooling the
coefficient of performance is cold
temperature over the difference in
temperatures so slightly different
equations depending on whether we're
heating or we're cooling
just to make sure
that concept
sticks a little better let's work an
example let's say we are using a heat
pump
in the winter to heat up our house
so let's say the outdoor temperature
in the winter is
5 degrees celsius or if you prefer
fahrenheit that's 41 degrees fahrenheit
so 273 plus 5 is 278 kelvin
and we're keeping the inside of our
house at a comfortable 68 fahrenheit or
20 celsius so 293
kelvin
and we'd like to know how efficient we
can expect a heat pump to be under those
circumstances
so we're using the heat pump in heating
mode so the equation we need is hot
temperature over the difference in
temperature so our hot temperature is
293 kelvin
temperature inside our house
the cold temperature is hot minus cold
293 minus 78
so that's 293 divided by 15 kelvin
and
mathematically that works out to be 19.5
so our coefficient of performance for a
heat pump run
on a day
with these temperatures
is 19.5
so the first thing we notice here
explains why i didn't want to call this
an efficiency this coefficient of
performance is typically very often
larger than one for a heat pump so we
means we have if we were calling it
efficiency if we said the efficiency was
greater than 100 percent that wouldn't
be wrong it's just a little bit
confusing it's not what we think of
efficiency as being
if heat's flowing downhill and we siphon
off a little bit of that to do work the
efficiency is just how much of it we can
manage to siphon off
in this case the amount of energy we
have to supply the pump energy uphill to
get it from the cold temperature to the
hot temperature in the form of heat
turns out that's a a pretty nice ratio
if i want to
dump 19 and a half joules worth of heat
into my house i've only got to pay for
one joule worth of electricity and that
will be enough to pay to suck 18 and a
half joules out of the out of the
outside and dump it into my house so
coefficient of performance is commonly
greater than one
because the heat heat engines are
inefficient and the consequence of that
fact is heat pumps tend to be quite
efficient
what that means is if you've ever paid
much attention to the energy efficiency
of your of your heat pump you may know
that heat pumps are much more
energy efficient way to heat your house
than
a heater a gas heater an electric heater
if you run a gas heater or or more
specifically an electric heater
every joule of energy you supply in the
form of gas or in the form of
electricity gets turned into heat so
that uh electric heater may be 100
efficient you might turn all the
electricity into heat but it can't
compete with a heat pump which is
generating
20 times as much heat in this case as
the amount of electricity that you
provide for it
so
that's an interesting fact to know about
heat pumps from an everyday point of
view but from a thermodynamic point of
view really the important thing we've
learned is that a heat pump is really
just the reverse of a heat engine
instead of letting heat flow downhill
and using that to do some work we're
pumping heat uphill and supplying work
in order to do that