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Heat Pump

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A heat pump operates as the exact thermodynamic reverse of a heat engine, functioning by moving heat against its natural tendency rather than utilizing it. While a heat engine naturally allows heat to flow from a hot reservoir to a cold one to perform work, similar to water flowing downhill to turn a wheel, a heat pump requires an input of work to force heat to flow uphill from a colder environment to a warmer space. This process is not spontaneous; just as pumping water from a low level to a high elevation requires energy, extracting thermal energy from cold outdoor air and transferring it into a warm house demands electrical work. Common examples of this technology include refrigerators, air conditioners, and central HVAC systems, all of which remove heat from a cooler interior area and reject it to a warmer exterior environment. The performance of a heat pump is measured not by efficiency in the traditional sense, but by a metric called the Coefficient of Performance (COP), which represents the ratio of useful heating or cooling benefit to the energy cost required to operate the system. When used for heating during winter, the COP is calculated as the hot temperature divided by the difference between the hot and cold temperatures. In this mode, the "benefit" is the total heat delivered into the warm space, which includes both the work supplied as electricity and the heat extracted from the outdoors. Consequently, the COP for heating is typically greater than one, meaning that for every unit of electrical energy consumed, the system delivers multiple units of thermal energy to the home. Conversely, when a heat pump operates in cooling mode, such as an air conditioner or a refrigerator, the definition of the benefit shifts to the amount of heat removed from the cold interior space rather than the total heat rejected outside. In this scenario, the COP is calculated using the cold temperature divided by the temperature difference, resulting in a value that is mathematically lower than the heating mode but still generally exceeds one. This high performance explains why heat pumps are significantly more energy-efficient than direct electric heaters or gas heaters; while a standard heater converts every joule of electricity directly into heat with a maximum efficiency of 100 percent, a heat pump leverages existing thermal energy from the environment to generate two to twenty times as much heat for the same amount of electrical input. Ultimately, the technology demonstrates that by supplying work to pump heat uphill, we can achieve substantial heating or cooling effects that far surpass simple conversion methods.
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[Music] all right so we have an understanding of what a heat engine is heat engine is a process that converts heat into work specifically by absorbing some amount of heat from a hot temperature reservoir using some of that heat to do work and having some leftover heat that it rejects to a cold temperature reservoir several times when talking about heat engines we've talked about the need for those processes to be reversible so if in fact they're reversible let's think about what happens if we actually reverse them if we change the direction of each of these arrows so remember the arrows indicate whether energy is flowing into the system or absorbing heat or whether it's flowing out of the system we're rejecting heat or we're doing work so if i redraw this figure just reversing each of these arrows so the hot heat process is flowing from the system to the surroundings the work is being done on the system rather than by the system and at the cold temperature heat is flowing out of the surroundings into the system i've just reversed all those arrows let's think about what that means if this process involves absorbing some heat at a high temperature using some of it to do work and letting the rest of it flow down to the cold temperature let me point out that it's no accident that i've drawn this figure with the hot temperature on top and the cold temperature on bottom it's it's a very natural process for heat to flow from the hot temperature to the cold temperature in fact when carneau came up with this idea of heat engines and this way to describe them he was thinking of something like a waterfall where it's very natural for water to flow from a high position to a low position and you can make use of the natural tendency for water to flow downhill to turn a water fill a water wheel to get some work out of the process as water flows from high to low same thing here heat will naturally flow from a hot temperature to a cold temperature we can make use of that natural tendency to do some work along the way when we reverse the process what these arrows describe is we're absorbing some amount of heat from a cold body from a cold reservoir we're going to put some amount of heat up into a hotter temperature so i've got a net amount of heat flow from a cold temperature to a hot temperature that's not a natural thing to happen it doesn't normally happen that heat flows from a cold thing to a hot thing so we have to actually do some work it costs us some energy in order to pump the heat from the cold temperature up to the hot temperature just as it would cost us some energy to pump water from a low level up to a high level so in analogy with that statement this process is called a heat pump and it's just the exact reverse of a heat engine some examples of heat pumps would be things like a refrigerator so that's exactly what we expect a refrigerator to do we think of refrigerator as a way to cool down our food but we have a cold inside of a refrigerator and we need to remove some heat from that cold place and we end up putting that heat in a hotter place so when you bring your groceries home and you put them in the refrigerator you want to remove some of the heat that's keeping those groceries at room temperature you want to cool them down so you're removing heat from the place from the cold surroundings costs you some electricity to do that and then you dump that excess heat out the back of the refrigerator so that's exactly what a refrigerator is doing it's also exactly what an air conditioner does if you have a window air conditioner in the window of a room it's removing heat from the cool inside of your house cooling it down further and dumping that excess heat out the window to a place that's probably warmer another example and this one is is perhaps the one to keep in your mind for the rest of this video because it's it's the best illustration and also the most confusing illustration of this idea of a heat pump so it's worth getting the details correct what we call a heat pump in a central air hvac system for a house for example is an example of a heat pump in the summer your heat pump works the same way as an air conditioner it's hot outside it's cool inside you want to keep it cool so you want to remove some heat from the inside and dump it out to the warmer outside so that's exactly what this heat pump is doing counter intuitively what your heat bump does in the winter when you warm up your house you know it's cold outside warm inside you want to make sure it stays warm inside so the way the heat bump works in the winter is it it uses exactly this process it extracts some heat from the outdoors from the cold winter outdoor air it extracts some heat from the cold air and dumps it into your house so your house is like the the place where the waste heat goes and you're using that waste heat to heat up your house so heat pump when you run it in the winter time it's removing heat from the outdoors dumping it into your house so heat pumps what we want to say about heat pumps is oh yes their efficiency how do we talk about the efficiency of a heat pump uh efficiency of a heat engine we've we've talked about before it's related to this ratio of temperatures t cold to t hot the efficiency of a heat pump we don't actually end up calling it efficiency so we're going to use a different term we're going to use beta this term beta we call it coefficient of performance and it will become clear in just a minute why i'm not going to call that an efficiency the coefficient of performance or cop for heat pump that's still philosophically going to be the amount of benefit energetically we get from the heat pump relative to how much it costs us to run the heat pump the definition of what the benefit is what the cost is depends on whether we're using it to heat something up or cool something down but the the basic idea is still the same so let's think about let's say first when we're using the heat pump to heat something up when we're running this heat pump in the winter and our benefit is the heating effect that we get from the heat pump you're using your heat pump to heat your house so the benefit you get from this heat pump is you pay some electricity to do some work to pump in this unnatural direction remove some heat from the cold outdoors and pump it into your warmer house so the benefit you're getting is this q sub h the cost doesn't cost you anything to remove the heat from the outside the cost to you is the amount of work that you have to do the electricity you have to pay to make this heat pump run so that's the cost let me make sure i have my signs right qh is a negative number so i want to make that negative on top so that the benefit to us is a positive amount of of heat so that's negative of this negative quantity and work is already a positive number so i'm going to leave that just the way it is so the way i can make sense out of this is the same thing we did before whether i look at this diagram or whether i look at this diagram the net change in energy of the system has to be zero if i combine all these arrows together so if i add up total amount of heat and total amount of work that has to be 0 so that let's say w is going to be minus qh minus qc so that's what i'll put in the denominator here i've got minus qh on top minus qh minus qc on bottom and that's too many negative signs so let me just get rid of all of them at the same time so qh over qh plus qc i want eventually to turn those q's into temperatures the way we did when we were talking about the energy i mean the efficiency of a heat pump remember we used the fact that the ratio of the heats is the negative of the ratio of the temperatures so maybe not the shortest but the way i can guarantee i won't make any mistakes let's divide through top and bottom by q sub h so qh becomes 1 qh becomes 1 qc becomes qc over qh then i've got this ratio qc over qh which i can write as negative tc over th and now that i've done that i don't like the way it looks with a fraction inside a fraction so let me go through and re-multiply by th in this case and what i'll get is so one becomes th one becomes th and tc over th becomes tc so the efficiency sorry not the efficiency the coefficient of performance for a heat pump being run in heating mode is this ratio hot temperature divided by hot minus cold so similar to efficiency of a heat engine in a sense that involves just the ratio of temperatures or difference in temperatures but it's a different combination of those we'll plug some numbers in in just a minute and see what kind of values we get for this coefficient of performance but before we do that let's run through the same calculation real quick if we're using our heat pump in cooling mode rather than in heating mode so if we're using our heat pump as an air conditioner as a refrigerator where the benefit we get to us is how much heat it removes from the inside of the refrigerator or the inside of the house when we're using our air conditioner or our heat pump so in this case the benefit that we get isn't the amount of waste heat that's dumped out the back of the refrigerator or out the outside the house when you're cooling your house the benefit we get is how much heat we extract from the inside of the house so the benefit we get is qc which is a positive number i want to divide that by the electricity cost or the amount of work i have to do in order to pump that heat up hill to the higher temperature reservoir so again the algebra is going to be almost the same but not quite the work in the denominator is minus qh minus qc um let's again flip the signs i want to make these positive and that one becomes negative so i've got if i divide through in this case again by qh i'll get minus qc over qh over 1 plus qc over qh now i can use the fact that the ratio of heats is equal to the negative the ratio of the temperatures so that'll be negative becomes positive tc over in the denominator i've got 1 minus t c over t h and then if i get rid of the fractions inside the fractions multiplying by t h gives me t c over t c no sorry t h minus t c notice that this result for cooling is not the same as this result for heating when i'm heating the coefficient of performance is hot temperature over the difference in temperatures when i'm cooling the coefficient of performance is cold temperature over the difference in temperatures so slightly different equations depending on whether we're heating or we're cooling just to make sure that concept sticks a little better let's work an example let's say we are using a heat pump in the winter to heat up our house so let's say the outdoor temperature in the winter is 5 degrees celsius or if you prefer fahrenheit that's 41 degrees fahrenheit so 273 plus 5 is 278 kelvin and we're keeping the inside of our house at a comfortable 68 fahrenheit or 20 celsius so 293 kelvin and we'd like to know how efficient we can expect a heat pump to be under those circumstances so we're using the heat pump in heating mode so the equation we need is hot temperature over the difference in temperature so our hot temperature is 293 kelvin temperature inside our house the cold temperature is hot minus cold 293 minus 78 so that's 293 divided by 15 kelvin and mathematically that works out to be 19.5 so our coefficient of performance for a heat pump run on a day with these temperatures is 19.5 so the first thing we notice here explains why i didn't want to call this an efficiency this coefficient of performance is typically very often larger than one for a heat pump so we means we have if we were calling it efficiency if we said the efficiency was greater than 100 percent that wouldn't be wrong it's just a little bit confusing it's not what we think of efficiency as being if heat's flowing downhill and we siphon off a little bit of that to do work the efficiency is just how much of it we can manage to siphon off in this case the amount of energy we have to supply the pump energy uphill to get it from the cold temperature to the hot temperature in the form of heat turns out that's a a pretty nice ratio if i want to dump 19 and a half joules worth of heat into my house i've only got to pay for one joule worth of electricity and that will be enough to pay to suck 18 and a half joules out of the out of the outside and dump it into my house so coefficient of performance is commonly greater than one because the heat heat engines are inefficient and the consequence of that fact is heat pumps tend to be quite efficient what that means is if you've ever paid much attention to the energy efficiency of your of your heat pump you may know that heat pumps are much more energy efficient way to heat your house than a heater a gas heater an electric heater if you run a gas heater or or more specifically an electric heater every joule of energy you supply in the form of gas or in the form of electricity gets turned into heat so that uh electric heater may be 100 efficient you might turn all the electricity into heat but it can't compete with a heat pump which is generating 20 times as much heat in this case as the amount of electricity that you provide for it so that's an interesting fact to know about heat pumps from an everyday point of view but from a thermodynamic point of view really the important thing we've learned is that a heat pump is really just the reverse of a heat engine instead of letting heat flow downhill and using that to do some work we're pumping heat uphill and supplying work in order to do that